Description
Can you now extract the secret key k from this encryption algorithm?
The flag format is as follows: ECSC{k in hex}.
This challenge has been split into two parts:
Files
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wb.py
1.49 MiB – 636e1d5ceca1cf99ce9b4eeddfca0f1e09a0d769cf226c5221209c40771cf2a8
Author
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